(20x^2-25x-30)/3x=((4x^2-28x+4)/3x)+5

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Solution for (20x^2-25x-30)/3x=((4x^2-28x+4)/3x)+5 equation:



(20x^2-25x-30)/3x=((4x^2-28x+4)/3x)+5
We move all terms to the left:
(20x^2-25x-30)/3x-(((4x^2-28x+4)/3x)+5)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 3x)+5)!=0
x!=0/1
x!=0
x∈R
We calculate fractions
(20x^2-25x-30)*3x)+5)/9x^2+(-(((4x^2-28x+4)*3x)/9x^2=0
We can not solve this equation

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